x^2-5.3=0

Solution for x^2-5.3=0 equation:

x^2-5.3=0

a = 1; b = 0; c = -5.3;
Δ = b2-4ac
Δ = 02-4·1·(-5.3)
Δ = 21.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{21.2}}{2*1}=\frac{0-\sqrt{21.2}}{2}
=-\frac{\sqrt{}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{21.2}}{2*1}=\frac{0+\sqrt{21.2}}{2}
=\frac{\sqrt{}}{2}
$